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4x^2-24=144
We move all terms to the left:
4x^2-24-(144)=0
We add all the numbers together, and all the variables
4x^2-168=0
a = 4; b = 0; c = -168;
Δ = b2-4ac
Δ = 02-4·4·(-168)
Δ = 2688
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2688}=\sqrt{64*42}=\sqrt{64}*\sqrt{42}=8\sqrt{42}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{42}}{2*4}=\frac{0-8\sqrt{42}}{8} =-\frac{8\sqrt{42}}{8} =-\sqrt{42} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{42}}{2*4}=\frac{0+8\sqrt{42}}{8} =\frac{8\sqrt{42}}{8} =\sqrt{42} $
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